Tutorialshore
if special characters are not displaying in php .if it is showing like “?” use below steps
1)Add below meta tag in between <head></head> section <meta charset=”utf-8” />
2) Use htmlentities function to display mysql query result
$value=htmlentities($row[‘name’]);
echo $value;
Today leading Malayalam actor Prithviraj Sukumaran , given special onam gift to malayalm film Industry by his Facebook post.He posted ,He will make his maiden directorial debut with starring superstar Mohanlal.The film name is “Lucifer”.
The film is producing under the banner of Aashirvad Cinemas by Antony Perumbavoor. The versatile film actor Murali Gopy will do the screenplay for the this film “Lucifer”.
‘Lucifer’ was planned by late director Rajesh Pillai and Murali Gopy,For Some time issue they postponed that project.This will going to reborn under the banner of Aashirvad Cinemas.
This Onam is big success for both Mohanlal and Prithviraj, for Mohanlal it is Oppam , for Prithviraj it is ‘Oozham’. ‘Lucifer’ is going to be bigger hit for both of them.
The complete actor Mohanlal confirmed the news by sharing in Facebook wall
“Here I have a big news for my million splendid audience about my upcoming project. A big budget movie from Antony Perumbavoor under the banner of Aashirvad Cinemas, which sees collaboration of two icons of Malayalam film industry behind the camera for the first time, who are also distinguished for their uniqueness … Prithviraj son of my dearest Sukumarettan doing his directorial debut and Murali Gopy son of our Gopiettan penning story and script … And the movie’s name is ‘LUCIFER’.”
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Database connection php mysql code
$servername = “localhost”;
$username = “username”;
$password = “password”;
$conn = mysql_connect($servername, $username, $password);
To select a database
mysql_select_db($con,”mydatabse”);
To prove that sinQ-cosQ+1/sinQ+cosQ-1 =1/secQ-tanQ
Consider LHS
LHS => SinQ-cosQ+1/sinQ+cosQ+1
=> (sinQ/cosQ-cosQ/cosQ+1/cosQ)/(sinQ/cosQ+cosQ/cosQ-1/cosQ) (divide nominator and denominate by cosQ)
=> (tanQ-1+secQ)/(tanQ+1-secQ)
=> (tanQ+secQ-1)/(tanQ-secQ+1)
=> (tanQ+secQ-1)/(tanQ-secQ+(sec²Q-tan²Q) (since sec²Q-tan²Q=1)
=> (tanQ+secQ-1)/(tanQ-secQ+[(secQ-tanQ)(secQ+tanQ)]
=> (tanQ+secQ-1)/-(secQ-tanQ)+[(secQ-tanQ)(secQ+tanQ)]
=>(tanQ+secQ-1)/(secQ-tanQ)[(secQ+tanQ)-1]
=> 1/secQ-tanQ (since (tanQ+secQ-1)/[(secQ+tanQ)-1]=1)
=> RHS
=> Hence Proved