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Here we have to prove sinQ cotQ + sinQ cosecQ = 1 + cosQ we will start with LHS (Left hand side ie sinQ cotQ + sinQ cosecQ ) and prove that it is equal to 1 + cosQ Hence we will get LHS = RHS
Proof
Lets start with LHS of the equations
LHS = sinQ cotQ + sinQ cosecQ
= sinQ (cosQ/sinQ) + sinQ * 1/sinQ
= cosQ + 1
= 1 + cosQ
Here we have to prove sinQ/cotQ + cosecQ = 2 + sinQ/cotQ – cosecQ we will start with LHS (Left hand side ie sinQ/cotQ + cosecQ ) and prove that it is equal to 2 + sinQ/cotQ – cosecQ Hence we will get LHS = RHS
Our aim is to Show that sinQ/cotQ + cosecQ = 2 + sinQ/cotQ – cosecQ
Proof
Lets start with LHS of the equations
LHS = sinQ/(cotQ + cosecQ)
= sinQ/(cosQ/sinQ + 1/sinQ)
= sinQ2 /(cosq+1)/sinQ
= sinQ2 /(1 + cosQ)
= sin²Q (1-cosQ) /(1 + cosQ)(1 – cosQ)
= sin²Q (1-cosQ) /(1 – cos2Q)
= sin²Q (1-cosQ) /sin²Q Hint : (1 – cos²Q) = sin²Q since sin²Q + cos²Q = 1
= 1-cosQ
RHS = 2 + sinQ/cotQ – cosecQ
= 2+ sinQ/(cosQ/sinQ-1/sinq)
= 2 +sin²q/(cosQ – 1)
= 2 -sin²q/(1-cosQ )
= 2 – sin²q(1 + cosQ)/(1-cosQ) (1 + cosQ)
= 2 – sin²q(1 + cosQ)/(1-cos²Q)
= 2 – sin²q(1 + cosQ)/sin²q Hint : (1 – cos²Q) = sin²Q since sin²Q + cos²Q = 1
= 2 – (1 + cosQ)
= 1 – cosQ
RHS = LHS
Hence proved
based on right-angled triangle their 6 ratios in Trigonometry, this are basically called Trigonometric functions .The six trigonometric functions are sine, cosine, secant, co-secant, tangent and co-tangent.The value of each function can be find out using below trigonometric formulas
Here are the definition of each of this trigonometric formulas
trigonometric formulas
sin θ = opposite Side/hypotenuse where θ is the angle cos θ = adjacent Side/hypotenuse where θ is the angle tan θ = opposite Side/adjacent Side where θ is the angle sec θ = hypotenuse/adjacent Side where θ is the angle cosec θ = hypotenuse/opposite Side where θ is the angle cot θ = adjacent Side/opposite Side where θ is the angle
As per the above table definition we can relate each of the formula in below ways
cosec θ = 1/sin θ hint : 1/opposite Side/hypotenuse = hypotenuse/opposite sec θ = 1/cos θ hint : 1/adjacent Side/hypotenuse = hypotenuse/adjacent Side cot θ = 1/tan θ hint : 1/opposite Side/adjacent = adjacent Side/opposite Side sin θ = 1/cosec θ hint : 1/hypotenuse/opposite Side = opposite Side/hypotenuse cos θ = 1/sec θ hint : 1/hypotenuse/adjacent Side =adjacent Side/hypotenuse tan θ = 1/cot θ hint : 1/adjacent Side/opposite Side = opposite Side/adjacent Side
we can find each of the six trigonometric functions values using above trigonometric formulas